# # # The Nimrod Compiler # (c) Copyright 2011 Andreas Rumpf # # See the file "copying.txt", included in this # distribution, for details about the copyright. # # tree helper routines import ast, astalgo, lexer, msgs, strutils, wordrecg proc hasSon(father, son: PNode): bool = for i in countup(0, sonsLen(father) - 1): if father.sons[i] == son: return true result = false proc cyclicTreeAux(n, s: PNode): bool = if n == nil: return false if hasSon(s, n): return true var m = sonsLen(s) addSon(s, n) if not (n.kind in {nkEmpty..nkNilLit}): for i in countup(0, sonsLen(n) - 1): if cyclicTreeAux(n.sons[i], s): return true result = false delSon(s, m) proc cyclicTree*(n: PNode): bool = var s = newNodeI(nkEmpty, n.info) result = cyclicTreeAux(n, s) proc ExprStructuralEquivalent*(a, b: PNode): bool = result = false if a == b: result = true elif (a != nil) and (b != nil) and (a.kind == b.kind): case a.kind of nkSym: # don't go nuts here: same symbol as string is enough: result = a.sym.name.id == b.sym.name.id of nkIdent: result = a.ident.id == b.ident.id of nkCharLit..nkInt64Lit: result = a.intVal == b.intVal of nkFloatLit..nkFloat64Lit: result = a.floatVal == b.floatVal of nkStrLit..nkTripleStrLit: result = a.strVal == b.strVal of nkEmpty, nkNilLit, nkType: result = true else: if sonsLen(a) == sonsLen(b): for i in countup(0, sonsLen(a) - 1): if not ExprStructuralEquivalent(a.sons[i], b.sons[i]): return result = true proc sameTree*(a, b: PNode): bool = result = false if a == b: result = true elif (a != nil) and (b != nil) and (a.kind == b.kind): if a.flags != b.flags: return if a.info.line != b.info.line: return if a.info.col != b.info.col: return #if a.info.fileIndex <> b.info.fileIndex then exit; case a.kind of nkSym: # don't go nuts here: same symbol as string is enough: result = a.sym.name.id == b.sym.name.id of nkIdent: result = a.ident.id == b.ident.id of nkCharLit..nkInt64Lit: result = a.intVal == b.intVal of nkFloatLit..nkFloat64Lit: result = a.floatVal == b.floatVal of nkStrLit..nkTripleStrLit: result = a.strVal == b.strVal of nkEmpty, nkNilLit, nkType: result = true else: if sonsLen(a) == sonsLen(b): for i in countup(0, sonsLen(a) - 1): if not sameTree(a.sons[i], b.sons[i]): return result = true proc getProcSym*(call: PNode): PSym = result = call.sons[0].sym proc getOpSym*(op: PNode): PSym = if not (op.kind in {nkCall, nkHiddenCallConv, nkCommand, nkCallStrLit}): result = nil else: if (sonsLen(op) <= 0): InternalError(op.info, "getOpSym") if op.sons[0].Kind == nkSym: result = op.sons[0].sym else: result = nil proc getMagic*(op: PNode): TMagic = case op.kind of nkCall, nkHiddenCallConv, nkCommand, nkCallStrLit, nkPrefix, nkPostfix, nkInfix: case op.sons[0].Kind of nkSym: result = op.sons[0].sym.magic else: result = mNone else: result = mNone proc TreeToSym*(t: PNode): PSym = result = t.sym proc isConstExpr*(n: PNode): bool = result = (n.kind in {nkCharLit..nkInt64Lit, nkStrLit..nkTripleStrLit, nkFloatLit..nkFloat64Lit, nkNilLit}) or (nfAllConst in n.flags) proc flattenTreeAux(d, a: PNode, op: TMagic) = if (getMagic(a) == op): # a is a "leaf", so add it: for i in countup(1, sonsLen(a) - 1): # BUGFIX flattenTreeAux(d, a.sons[i], op) else: addSon(d, copyTree(a)) proc flattenTree*(root: PNode, op: TMagic): PNode = result = copyNode(root) if (getMagic(root) == op): # BUGFIX: forget to copy prc addSon(result, copyNode(root.sons[0])) flattenTreeAux(result, root, op) proc SwapOperands*(op: PNode) = var tmp = op.sons[1] op.sons[1] = op.sons[2] op.sons[2] = tmp proc IsRange*(n: PNode): bool {.inline.} = if n.kind == nkInfix: if n[0].kind == nkIdent and n[0].ident.id == ord(wDotDot) or n[0].kind == nkSymChoice and n[0][1].sym.name.id == ord(wDotDot): result = true