#
#
#            Nim's Runtime Library
#        (c) Copyright 2018 Nim contributors
#
#    See the file "copying.txt", included in this
#    distribution, for details about the copyright.
#

## This module implements an algorithm to compute the
## `diff`:idx: between two sequences of lines.

# code owner: Arne Döring
#
# This is based on C# code written by Matthias Hertel, http://www.mathertel.de
#
# This Class implements the Difference Algorithm published in
# "An O(ND) Difference Algorithm and its Variations" by Eugene Myers
# Algorithmica Vol. 1 No. 2, 1986, p 251.

import tables, strutils

type
  Item* = object    ## An Item in the list of differences.
    startA*: int    ## Start Line number in Data A.
    startB*: int    ## Start Line number in Data B.
    deletedA*: int  ## Number of changes in Data A.
    insertedB*: int ## Number of changes in Data B.

  DiffData = object ## Data on one input file being compared.
    data: seq[int] ## Buffer of numbers that will be compared.
    modified: seq[bool] ## Array of booleans that flag for modified
                        ## data. This is the result of the diff.
                        ## This means deletedA in the first Data or
                        ## inserted in the second Data.

  Smsrd = object
    x, y: int

# template to avoid a seq copy. Required until ``sink`` parameters are ready.
template newDiffData(initData: seq[int]; L: int): DiffData =
  DiffData(
    data: initData,
    modified: newSeq[bool](L + 2)
  )

proc len(d: DiffData): int {.inline.} = d.data.len

proc diffCodes(aText: string; h: var Table[string, int]): DiffData =
  ## This function converts all textlines of the text into unique numbers for every unique textline
  ## so further work can work only with simple numbers.
  ## ``aText`` the input text
  ## ``h`` This extern initialized hashtable is used for storing all ever used textlines.
  ## ``trimSpace`` ignore leading and trailing space characters
  ## Returns a array of integers.
  var lastUsedCode = h.len
  result.data = newSeq[int]()
  for s in aText.splitLines:
    if h.contains s:
      result.data.add h[s]
    else:
      inc lastUsedCode
      h[s] = lastUsedCode
      result.data.add lastUsedCode
  result.modified = newSeq[bool](result.data.len + 2)

proc optimize(data: var DiffData) =
  ## If a sequence of modified lines starts with a line that contains the same content
  ## as the line that appends the changes, the difference sequence is modified so that the
  ## appended line and not the starting line is marked as modified.
  ## This leads to more readable diff sequences when comparing text files.
  var startPos = 0
  while startPos < data.len:
    while startPos < data.len and not data.modified[startPos]:
      inc startPos
    var endPos = startPos
    while endPos < data.len and data.modified[endPos]:
      inc endPos

    if endPos < data.len and data.data[startPos] == data.data[endPos]:
      data.modified[startPos] = false
      data.modified[endPos] = true
    else:
      startPos = endPos

proc sms(dataA: var DiffData; lowerA, upperA: int; dataB: DiffData; lowerB, upperB: int;
         downVector, upVector: var openArray[int]): Smsrd =
  ## This is the algorithm to find the Shortest Middle Snake (sms).
  ## ``dataA`` sequence A
  ## ``lowerA`` lower bound of the actual range in dataA
  ## ``upperA`` upper bound of the actual range in dataA (exclusive)
  ## ``dataB`` sequence B
  ## ``lowerB`` lower bound of the actual range in dataB
  ## ``upperB`` upper bound of the actual range in dataB (exclusive)
  ## ``downVector`` a vector for the (0,0) to (x,y) search. Passed as a parameter for speed reasons.
  ## ``upVector`` a vector for the (u,v) to (N,M) search. Passed as a parameter for speed reasons.
  ## Returns a MiddleSnakeData record containing x,y and u,v.

  let max = dataA.len + dataB.len + 1

  let downK = lowerA - lowerB # the k-line to start the forward search
  let upK = upperA - upperB # the k-line to start the reverse search

  let delta = (upperA - lowerA) - (upperB - lowerB)
  let oddDelta = (delta and 1) != 0

  # The vectors in the publication accepts negative indexes. the vectors implemented here are 0-based
  # and are access using a specific offset: upOffset upVector and downOffset for downVector
  let downOffset = max - downK
  let upOffset = max - upK

  let maxD = ((upperA - lowerA + upperB - lowerB) div 2) + 1

  downVector[downOffset + downK + 1] = lowerA
  upVector[upOffset + upK - 1] = upperA

  for D in 0 .. maxD:
    # Extend the forward path.
    for k in countUp(downK - D, downK + D, 2):
      # find the only or better starting point
      var x: int
      if k == downK - D:
        x = downVector[downOffset + k + 1] # down
      else:
        x = downVector[downOffset + k - 1] + 1 # a step to the right
        if k < downK + D and downVector[downOffset + k + 1] >= x:
          x = downVector[downOffset + k + 1] # down

      var y = x - k

      # find the end of the furthest reaching forward D-path in diagonal k.
      while x < upperA and y < upperB and dataA.data[x] == dataB.data[y]:
        inc x
        inc y

      downVector[downOffset + k] = x

      # overlap ?
      if oddDelta and upK - D < k and k < upK + D:
        if upVector[upOffset + k] <= downVector[downOffset + k]:
          return Smsrd(x: downVector[downOffset + k],
                       y: downVector[downOffset + k] - k)

    # Extend the reverse path.
    for k in countUp(upK - D, upK + D, 2):
      # find the only or better starting point
      var x: int
      if k == upK + D:
        x = upVector[upOffset + k - 1] # up
      else:
        x = upVector[upOffset + k + 1] - 1 # left
        if k > upK - D and upVector[upOffset + k - 1] < x:
          x = upVector[upOffset + k - 1] # up

      var y = x - k
      while x > lowerA and y > lowerB and dataA.data[x - 1] == dataB.data[y - 1]:
        dec x
        dec y

      upVector[upOffset + k] = x

      # overlap ?
      if not oddDelta and downK-D <= k and k <= downK+D:
        if upVector[upOffset + k] <= downVector[downOffset + k]:
          return Smsrd(x: downVector[downOffset + k],
                       y: downVector[downOffset + k] - k)

  assert false, "the algorithm should never come here."

proc lcs(dataA: var DiffData; lowerA, upperA: int; dataB: var DiffData; lowerB, upperB: int;
         downVector, upVector: var openArray[int]) =
  ## This is the divide-and-conquer implementation of the longes common-subsequence (lcs)
  ## algorithm.
  ## The published algorithm passes recursively parts of the A and B sequences.
  ## To avoid copying these arrays the lower and upper bounds are passed while the sequences stay constant.
  ## ``dataA`` sequence A
  ## ``lowerA`` lower bound of the actual range in dataA
  ## ``upperA`` upper bound of the actual range in dataA (exclusive)
  ## ``dataB`` sequence B
  ## ``lowerB`` lower bound of the actual range in dataB
  ## ``upperB`` upper bound of the actual range in dataB (exclusive)
  ## ``downVector`` a vector for the (0,0) to (x,y) search. Passed as a parameter for speed reasons.
  ## ``upVector`` a vector for the (u,v) to (N,M) search. Passed as a parameter for speed reasons.

  # make mutable copy:
  var lowerA = lowerA
  var lowerB = lowerB
  var upperA = upperA
  var upperB = upperB

  # Fast walkthrough equal lines at the start
  while lowerA < upperA and lowerB < upperB and dataA.data[lowerA] == dataB.data[lowerB]:
    inc lowerA
    inc lowerB

  # Fast walkthrough equal lines at the end
  while lowerA < upperA and lowerB < upperB and dataA.data[upperA - 1] == dataB.data[upperB - 1]:
    dec upperA
    dec upperB

  if lowerA == upperA:
    # mark as inserted lines.
    while lowerB < upperB:
      dataB.modified[lowerB] = true
      inc lowerB

  elif lowerB == upperB:
    # mark as deleted lines.
    while lowerA < upperA:
      dataA.modified[lowerA] = true
      inc lowerA

  else:
    # Find the middle snakea and length of an optimal path for A and B
    let smsrd = sms(dataA, lowerA, upperA, dataB, lowerB, upperB, downVector, upVector)
    # Debug.Write(2, "MiddleSnakeData", String.Format("{0},{1}", smsrd.x, smsrd.y))

    # The path is from LowerX to (x,y) and (x,y) to UpperX
    lcs(dataA, lowerA, smsrd.x, dataB, lowerB, smsrd.y, downVector, upVector)
    lcs(dataA, smsrd.x, upperA, dataB, smsrd.y, upperB, downVector, upVector)  # 2002.09.20: no need for 2 points

proc createDiffs(dataA, dataB: DiffData): seq[Item] =
  ## Scan the tables of which lines are inserted and deleted,
  ## producing an edit script in forward order.
  var startA = 0
  var startB = 0
  var lineA = 0
  var lineB = 0
  while lineA < dataA.len or lineB < dataB.len:
    if lineA < dataA.len and not dataA.modified[lineA] and
       lineB < dataB.len and not dataB.modified[lineB]:
      # equal lines
      inc lineA
      inc lineB
    else:
      # maybe deleted and/or inserted lines
      startA = lineA
      startB = lineB

      while lineA < dataA.len and (lineB >= dataB.len or dataA.modified[lineA]):
        inc lineA

      while lineB < dataB.len and (lineA >= dataA.len or dataB.modified[lineB]):
        inc lineB

      if (startA < lineA) or (startB < lineB):
        result.add Item(startA: startA,
                        startB: startB,
                        deletedA: lineA - startA,
                        insertedB: lineB - startB)


proc diffInt*(arrayA, arrayB: openArray[int]): seq[Item] =
  ## Find the difference in 2 arrays of integers.
  ##
  ## ``arrayA`` A-version of the numbers (usualy the old one)
  ##
  ## ``arrayB`` B-version of the numbers (usualy the new one)
  ##
  ## Returns a array of Items that describe the differences.

  # The A-Version of the data (original data) to be compared.
  var dataA = newDiffData(@arrayA, arrayA.len)

  # The B-Version of the data (modified data) to be compared.
  var dataB = newDiffData(@arrayB, arrayB.len)

  let max = dataA.len + dataB.len + 1
  ## vector for the (0,0) to (x,y) search
  var downVector = newSeq[int](2 * max + 2)
  ## vector for the (u,v) to (N,M) search
  var upVector = newSeq[int](2 * max + 2)

  lcs(dataA, 0, dataA.len, dataB, 0, dataB.len, downVector, upVector)
  result = createDiffs(dataA, dataB)

proc diffText*(textA, textB: string): seq[Item] =
  ## Find the difference in 2 text documents, comparing by textlines.
  ##
  ## The algorithm itself is comparing 2 arrays of numbers so when comparing 2 text documents
  ## each line is converted into a (hash) number. This hash-value is computed by storing all
  ## textlines into a common hashtable so i can find dublicates in there, and generating a
  ## new number each time a new textline is inserted.
  ##
  ## ``textA`` A-version of the text (usually the old one)
  ##
  ## ``textB`` B-version of the text (usually the new one)
  ##
  ## Returns a seq of Items that describe the differences.

  # prepare the input-text and convert to comparable numbers.
  var h = initTable[string, int]()  # TextA.len + TextB.len  <- probably wrong initial size
  # The A-Version of the data (original data) to be compared.
  var dataA = diffCodes(textA, h)

  # The B-Version of the data (modified data) to be compared.
  var dataB = diffCodes(textB, h)

  h.clear # free up hashtable memory (maybe)

  let max = dataA.len + dataB.len + 1
  ## vector for the (0,0) to (x,y) search
  var downVector = newSeq[int](2 * max + 2)
  ## vector for the (u,v) to (N,M) search
  var upVector = newSeq[int](2 * max + 2)

  lcs(dataA, 0, dataA.len, dataB, 0, dataB.len, downVector, upVector)

  optimize(dataA)
  optimize(dataB)
  result = createDiffs(dataA, dataB)

when isMainModule:

  proc testHelper(f: seq[Item]): string =
    for it in f:
      result.add(
        $it.deletedA & "." & $it.insertedB & "." & $it.startA & "." & $it.startB & "*"
      )

  proc main() =
    var a, b: string

    stdout.writeLine("Diff Self Test...")

    # test all changes
    a = "a,b,c,d,e,f,g,h,i,j,k,l".replace(',', '\n')
    b = "0,1,2,3,4,5,6,7,8,9".replace(',', '\n')
    assert(testHelper(diffText(a, b)) ==
      "12.10.0.0*",
      "all-changes test failed.")
    stdout.writeLine("all-changes test passed.")
    # test all same
    a = "a,b,c,d,e,f,g,h,i,j,k,l".replace(',', '\n')
    b = a
    assert(testHelper(diffText(a, b)) ==
      "",
      "all-same test failed.")
    stdout.writeLine("all-same test passed.")

    # test snake
    a = "a,b,c,d,e,f".replace(',', '\n')
    b = "b,c,d,e,f,x".replace(',', '\n')
    assert(testHelper(diffText(a, b)) ==
      "1.0.0.0*0.1.6.5*",
      "snake test failed.")
    stdout.writeLine("snake test passed.")

    # 2002.09.20 - repro
    a = "c1,a,c2,b,c,d,e,g,h,i,j,c3,k,l".replace(',', '\n')
    b = "C1,a,C2,b,c,d,e,I1,e,g,h,i,j,C3,k,I2,l".replace(',', '\n')
    assert(testHelper(diffText(a, b)) ==
      "1.1.0.0*1.1.2.2*0.2.7.7*1.1.11.13*0.1.13.15*",
      "repro20020920 test failed.")
    stdout.writeLine("repro20020920 test passed.")

    # 2003.02.07 - repro
    a = "F".replace(',', '\n')
    b = "0,F,1,2,3,4,5,6,7".replace(',', '\n')
    assert(testHelper(diffText(a, b)) ==
      "0.1.0.0*0.7.1.2*",
      "repro20030207 test failed.")
    stdout.writeLine("repro20030207 test passed.")

    # Muegel - repro
    a = "HELLO\nWORLD"
    b = "\n\nhello\n\n\n\nworld\n"
    assert(testHelper(diffText(a, b)) ==
      "2.8.0.0*",
      "repro20030409 test failed.")
    stdout.writeLine("repro20030409 test passed.")

    # test some differences
    a = "a,b,-,c,d,e,f,f".replace(',', '\n')
    b = "a,b,x,c,e,f".replace(',', '\n')
    assert(testHelper(diffText(a, b)) ==
      "1.1.2.2*1.0.4.4*1.0.7.6*",
      "some-changes test failed.")
    stdout.writeLine("some-changes test passed.")

    # test one change within long chain of repeats
    a = "a,a,a,a,a,a,a,a,a,a".replace(',', '\n')
    b = "a,a,a,a,-,a,a,a,a,a".replace(',', '\n')
    assert(testHelper(diffText(a, b)) ==
      "0.1.4.4*1.0.9.10*",
      "long chain of repeats test failed.")

    stdout.writeLine("End.")
    stdout.flushFile

  main()