## add the first 10 numbers, and return the result in the exit code # # To run: # $ subx translate ex3.subx ex3 # $ subx run ex3 # Expected result: # $ echo $? # 55 == 0x08048054 # code segment, after leaving room for ELF header # instruction effective address operand displacement immediate # op subop mod rm32 base index scale r32 # 1-3 bytes 3 bits 2 bits 3 bits 3 bits 3 bits 2 bits 2 bits 0/1/2/4 bytes 0/1/2/4 bytes # result: EBX = 0 # 0: e_entry = 0x08048054 bb 0/imm32 # copy 0 to EBX # counter: ECX = 1 b9 1/imm32 # copy 1 to ECX # 10: loop: 0x0804805e # while (ECX <= 10) 81 7/subop/compare 3/mod/direct 1/rm32/ecx 0xa/imm32 # compare ECX, 10/imm 7f 0xa/disp8 # jump-if-greater exit (+10 bytes) # EBX += ECX 01 3/mod/direct 3/rm32/ebx 1/r32/ecx # add ECX to EBX # ECX++ 81 0/subop/add 3/mod/direct 1/rm32/ecx 1/imm32 # add 1 to ECX # loop eb -0x12/disp8 # jump loop (-18 bytes) # 28: exit: 0x08048070 # exit(EBX) b8 1/imm32 # copy 1 to EAX cd 0x80/imm8 # int 80h # vim:ft=subx:nowrap