## Example showing arg order on the stack.
# Show difference between ascii codes of first letter of first arg and first
# letter of second arg.
#
# To run:
#   $ subx translate ex9.subx ex9
#   $ subx run ex9 z x
# Expected result:
#   $ echo $?
#   2
#
# At the start of a SubX program:
#   argc: *ESP
#   argv[0]: *(ESP+4)
#   argv[1]: *(ESP+8)
#   ...
# Locals start from ESP-4 downwards.

== code
# instruction                     effective address                                                   operand     displacement    immediate
# op          subop               mod             rm32          base        index         scale       r32
# 1-3 bytes   3 bits              2 bits          3 bits        3 bits      3 bits        2 bits      2 bits      0/1/2/4 bytes   0/1/2/4 bytes
  # s1 = argv[1] (EAX)
  8b/copy                         1/mod/*+disp8   4/rm32/sib    4/base/ESP  4/index/none              0/r32/EAX   8/disp8         .                 # copy *(ESP+8) to EAX
  # s2 = argv[2] (EBX)
  8b/copy                         1/mod/*+disp8   4/rm32/sib    4/base/ESP  4/index/none              3/r32/EBX   0xc/disp8       .                 # copy *(ESP+12) to EBX
  # call string_equal(s1, s2)
    # push args
  50/push-EAX
  53/push-EBX
    # call
  e8/call  ascii_difference/disp32
    # discard args
  81          0/subop/add         3/mod/direct    4/rm32/ESP    .           .             .           .           .               8/imm32           # add 8 to ESP
  # exit(EAX)
  89/copy                         3/mod/direct    3/rm32/EBX    .           .             .           0/r32/EAX   .               .                 # copy EAX to EBX
  b8/copy                         .               .             .           .             .           .           .               1/imm32/exit      # copy 1 to EAX
  cd/syscall  0x80/imm8

ascii_difference:  # (s1, s2) : null-terminated ascii strings
  # a = first letter of s1 (ECX)
  8b/copy                         1/mod/*+disp8   4/rm32/sib    4/base/ESP  4/index/none              0/r32/EAX   8/disp8         .                 # copy *(ESP+8) to EAX
  8b/copy                         0/mod/indirect  0/rm32/EAX    .           .             .           0/r32/EAX   .               .                 # copy *EAX to EAX
  # b = first letter of s2 (EDX)
  8b/copy                         1/mod/*+disp8   4/rm32/sib    4/base/ESP  4/index/none              1/r32/ECX   4/disp8                           # copy *(ESP+4) to ECX
  8b/copy                         0/mod/indirect  1/rm32/ECX    .           .             .           1/r32/ECX   .               .                 # copy *ECX to ECX
  # a-b
  29/subtract                     3/mod/direct    0/rm32/EAX    .           .             .           1/r32/ECX   .               .                 # subtract ECX from EAX
  c3/return