## Example showing arg order on the stack. # Show difference between ascii codes of first letter of first arg and first # letter of second arg. # # To run: # $ subx translate ex9.subx ex9 # $ subx run ex9 z x # Expected result: # $ echo $? # 2 # # At the start of a SubX program: # argc: *ESP # argv[0]: *(ESP+4) # argv[1]: *(ESP+8) # ... # Locals start from ESP-4 downwards. == code # instruction effective address operand displacement immediate # op subop mod rm32 base index scale r32 # 1-3 bytes 3 bits 2 bits 3 bits 3 bits 3 bits 2 bits 2 bits 0/1/2/4 bytes 0/1/2/4 bytes # s1 = argv[1] (EAX) 8b/copy 1/mod/*+disp8 4/rm32/sib 4/base/ESP 4/index/none 0/r32/EAX 8/disp8 . # copy *(ESP+8) to EAX # s2 = argv[2] (EBX) 8b/copy 1/mod/*+disp8 4/rm32/sib 4/base/ESP 4/index/none 3/r32/EBX 0xc/disp8 . # copy *(ESP+12) to EBX # call string_equal(s1, s2) # push args 50/push . . . . . . . . # push EAX 53/push . . . . . . . . # push EBX # call e8/call ascii_difference/disp32 # discard args 81 0/subop/add 3/mod/direct 4/rm32/ESP . . . . . 8/imm32 # add 8 to ESP # exit(EAX) 89/copy 3/mod/direct 3/rm32/EBX . . . 0/r32/EAX . . # copy EAX to EBX b8/copy . . . . . . . 1/imm32/exit # copy 1 to EAX cd/syscall 0x80/imm8 ascii_difference: # (s1, s2) : null-terminated ascii strings # a = first letter of s1 (ECX) 8b/copy 1/mod/*+disp8 4/rm32/sib 4/base/ESP 4/index/none 0/r32/EAX 8/disp8 # copy *(ESP+8) to EAX 8b/copy 0/mod/indirect 0/rm32/EAX . . . 0/r32/EAX . . # copy *EAX to EAX # b = first letter of s2 (EDX) 8b/copy 1/mod/*+disp8 4/rm32/sib 4/base/ESP 4/index/none 1/r32/ECX 4/disp8 # copy *(ESP+4) to ECX 8b/copy 0/mod/indirect 1/rm32/ECX . . . 1/r32/ECX . . # copy *ECX to ECX # a-b 29/subtract 3/mod/direct 0/rm32/EAX . . . 1/r32/ECX . . # subtract ECX from EAX c3/return