From b815e39fc6ce94155b66f7e536fbc2b64294628b Mon Sep 17 00:00:00 2001 From: Crystal Date: Mon, 16 Oct 2023 21:52:20 +0100 Subject: Finally, an update --- uni_notes/algebra.html | 352 ++++++++++++++++++++++++------------------------- 1 file changed, 176 insertions(+), 176 deletions(-) (limited to 'uni_notes') diff --git a/uni_notes/algebra.html b/uni_notes/algebra.html index 27c8d76..9323119 100755 --- a/uni_notes/algebra.html +++ b/uni_notes/algebra.html @@ -3,7 +3,7 @@ "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> - + Algebra 1 @@ -47,13 +47,13 @@

Algebra 1

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Contenu de la Matiére

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Contenu de la Matiére

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Rappels et compléments (11H)

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Rappels et compléments (11H)

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  • Logique mathématique et méthodes du raisonnement mathématique
  • Ensembles et Relations
  • @@ -61,9 +61,9 @@
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Structures Algébriques (11H)

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Structures Algébriques (11H)

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  • Groupes et morphisme de groupes
  • Anneaux et morphisme d’anneaux
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Polynômes et fractions rationnelles

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Polynômes et fractions rationnelles

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  • Notion du polynôme à une indéterminée á coefficients dans un anneau
  • Opérations Algébriques sur les polynômes
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Premier cours : Logique mathématique et méthodes du raisonnement mathématique Sep 25 :

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Premier cours : Logique mathématique et méthodes du raisonnement mathématique Sep 25 :

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Let P Q and R be propositions which can either be True or False. And let’s also give the value 1 to each True proposition and 0 to each false one.

@@ -438,13 +438,13 @@ A proposition is equivalent to another only when both of them have the same v Note: P implying Q is equivalent to P̅ implying Q̅, or: (P ⇒ Q) ⇔ (P̅ ⇒ Q̅)

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Properties:

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Properties:

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Absorption:

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Absorption:

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(P ∨ P) ⇔ P

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Commutativity:

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Commutativity:

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(P ∧ Q) ⇔ (Q ∧ P)

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Associativity:

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Associativity:

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P ∧ (Q ∧ R) ⇔ (P ∧ Q) ∧ R

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Distributivity:

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Distributivity:

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P ∧ (Q ∨ R) ⇔ (P ∧ Q) ∨ (P ∧ R)

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Neutral element:

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Neutral element:

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We define proposition T to be always true and F to be always false

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Negation of a conjunction & a disjunction:

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Negation of a conjunction & a disjunction:

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Now we won’t use bars here because my lazy ass doesn’t know how, so instead I will use not()!!!

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Transitivity:

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Transitivity:

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-[(P ⇒ Q) (Q ⇒ R)] ⇔ P ⇒ R +[(P ⇒ Q) AND (Q ⇒ R)] ⇔ P ⇒ R

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Contraposition:

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Contraposition:

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(P ⇒ Q) ⇔ (Q̅ ⇒ P̅)

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God only knows what this property is called:

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God only knows what this property is called:

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If

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-(Q̅ ⇒ Q) is true +(P̅ ⇒ Q) is true

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Some exercices I found online :

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Some exercices I found online :

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USTHB 2022/2023 Section B :

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USTHB 2022/2023 Section B :

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  • Exercice 1: Démontrer les équivalences suivantes:
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  • Exercice 1: Démontrer les équivalences suivantes:
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    1. (P ⇒ Q) ⇔ (Q̅ ⇒ P̅) @@ -635,8 +635,8 @@ Literally the same as above 🩷

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  • Exercice 2: Dire si les propositions suivantes sont vraies ou fausses, et les nier:
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  • Exercice 2: Dire si les propositions suivantes sont vraies ou fausses, et les nier:
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    1. ∀x ∈ ℝ ,∃y ∈ ℝ*+, tels que e^x = y @@ -769,13 +769,13 @@ y + x < 8

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2éme cours Oct 2

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2éme cours Oct 2

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Quantifiers

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Quantifiers

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A propriety P can depend on a parameter x

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  • Example
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  • Example
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    P(x) : x+1≥0

    @@ -803,13 +803,13 @@ P(X) is True or False depending on the values of x
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Proprieties

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Proprieties

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  • Propriety Number 1:
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  • Propriety Number 1:
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    The negation of the universal quantifier is the existential quantifier, and vice-versa :

    @@ -820,8 +820,8 @@ The negation of the universal quantifier is the existential quantifier, and vice
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  • Example:
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  • Example:
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    ∀ x ≥ 1 x² > 5 ⇔ ∃ x ≥ 1 x² < 5

    @@ -829,8 +829,8 @@ The negation of the universal quantifier is the existential quantifier, and vice
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  • Propriety Number 2:
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  • Propriety Number 2:
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    ∀x ∈ E, [P(x) ∧ Q(x)] ⇔ [∀ x ∈ E, P(x)] ∧ [∀ x ∈ E, Q(x)]

    @@ -841,8 +841,8 @@ The propriety “For any value of x from a set E , P(x) and Q(x)” is e

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    • Example :
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    • Example :
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      P(x) : sqrt(x) > 0 ; Q(x) : x ≥ 1

      @@ -860,8 +860,8 @@ P(x) : sqrt(x) > 0 ; Q(x) : x ≥ 1
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  • Propriety Number 3:
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  • Propriety Number 3:
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    ∃ x ∈ E, [P(x) ∧ Q(x)] [∃ x ∈ E, P(x)] ∧ [∃ x ∈ E, Q(x)]

    @@ -872,8 +872,8 @@ P(x) : sqrt(x) > 0 ; Q(x) : x ≥ 1

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    • Example of why it’s NOT an equivalence :
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    • Example of why it’s NOT an equivalence :
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      P(x) : x > 5 ; Q(x) : x < 5

      @@ -886,8 +886,8 @@ Of course there is no value of x such as its inferior and superior to 5 at the s
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  • Propriety Number 4:
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  • Propriety Number 4:
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    [∀ x ∈ E, P(x)] ∨ [∀ x ∈ E, Q(x)] ∀x ∈ E, [P(x) ∨ Q(x)]

    @@ -901,16 +901,16 @@ Of course there is no value of x such as its inferior and superior to 5 at the s
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    Multi-parameter proprieties :

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    Multi-parameter proprieties :

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    A propriety P can depend on two or more parameters, for convenience we call them x,y,z…etc

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      P(x,y): x+y > 0

      @@ -926,8 +926,8 @@ P(-2,-1) is a False one

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    • WARNING :
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    • WARNING :
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      ∀x ∈ E, ∃y ∈ F , P(x,y)

      @@ -943,8 +943,8 @@ Are different because in the first one y depends on x, while in the second one,

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      • Example :
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        ∀ x ∈ ℕ , ∃ y ∈ ℕ y > x -–— True

        @@ -958,8 +958,8 @@ Are different because in the first one y depends on x, while in the second one,
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  • Proprieties :
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  • Proprieties :
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    1. not(∀x ∈ E ,∃y ∈ F P(x,y)) ⇔ ∃x ∈ E, ∀y ∈ F not(P(x,y))
    2. not(∃x ∈ E ,∀y ∈ F P(x,y)) ⇔ ∀x ∈ E, ∃y ∈ F not(P(x,y))
    3. @@ -968,20 +968,20 @@ Are different because in the first one y depends on x, while in the second one,
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    Methods of mathematical reasoning :

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    Methods of mathematical reasoning :

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    Direct reasoning :

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    Direct reasoning :

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    To show that an implication P ⇒ Q is true, we suppose that P is true and we show that Q is true

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    • Example:
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      Let a,b be two Real numbers, we have to prove that a² + b² = 1 ⇒ |a + b| ≤ 2

      @@ -1024,9 +1024,9 @@ a²+b²=1 ⇒ |a + b| ≤ 2 Which is what we wanted to prove, therefor the im
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    Reasoning by the Absurd:

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    Reasoning by the Absurd:

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    To prove that a proposition is True, we suppose that it’s False and we must come to a contradiction

    @@ -1037,8 +1037,8 @@ And to prove that an implication P ⇒ Q is true using the reasoning by the absu

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      Prove that this proposition is correct using the reasoning by the absurd : ∀x ∈ ℝ* , sqrt(1+x²) ≠ 1 + x²/2

      @@ -1056,17 +1056,17 @@ sqrt(1+x²) = 1 + x²/2 ; 1 + x² = (1+x²/2)² ; 1 + x² = 1 + x^4/4 + x² ;
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    Reasoning by contraposition:

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    Reasoning by contraposition:

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    If an implication P ⇒ Q is too hard to prove, we just have to prove not(Q) ⇒ not(P) is true !!! or in other words that both not(P) and not(Q) are true

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    Reasoning by counter example:

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    Reasoning by counter example:

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    To prove that a proposition ∀x ∈ E, P(x) is false, all we have to do is find a single value of x from E such as not(P(x)) is true

    @@ -1074,20 +1074,20 @@ To prove that a proposition ∀x ∈ E, P(x) is false, all we have to do is find
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    3eme Cours : Oct 9

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    3eme Cours : Oct 9

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    Reasoning by recurrence :

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    Reasoning by recurrence :

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    P is a propriety dependent of n ∈ ℕ. If for n0 ∈ ℕ P(n0) is true, and if for n ≥ n0 (P(n) ⇒ P(n+1)) is true. Then P(n) is true for n ≥ n0

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    • Example:
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      Let’s prove that ∀ n ≥ 1 , (n,k=1)Σk = [n(n+1)]/2

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    4eme Cours : Chapitre 2 : Sets and Operations

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    4eme Cours : Chapitre 2 : Sets and Operations

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    Definition of a set :

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    Definition of a set :

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    A set is a collection of objects that share the sane propriety

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    Belonging, inclusion, and equality :

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    Belonging, inclusion, and equality :

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    1. Let E be a set. If x is an element of E, we say that x belongs to E we write x ∈ E, and if it doesn’t, we write x ∉ E
    2. A set E is included in a set F if all elements of E are elements of F and we write E ⊂ F ⇔ (∀x , x ∈ E ⇒ x ∈ F). We say that E is a subset of F, or a part of F. The negation of this propriety is : E ⊄ F ⇔ ∃x , x ∈ E and x ⊄ F
    3. @@ -1146,13 +1146,13 @@ A set is a collection of objects that share the sane propriety
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    Intersections and reunions :

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    Intersections and reunions :

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    Intersection:

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    Intersection:

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    E ∩ F = {x / x ∈ E AND x ∈ F} ; x ∈ E ∩ F ⇔ x ∈ F AND x ∈ F

    @@ -1163,9 +1163,9 @@ x ∉ E ∩ F ⇔ x ∉ E OR x ∉ F

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    Union:

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    Union:

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    E ∪ F = {x / x ∈ E OR x ∈ F} ; x ∈ E ∪ F ⇔ x ∈ F OR x ∈ F

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    Difference between two sets:

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    Difference between two sets:

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    E\F(Which is also written as : E - F) = {x / x ∈ E and x ∉ F}

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    Complimentary set:

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    Complimentary set:

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    If F ⊂ E. E - F is the complimentary of F in E.

    @@ -1197,52 +1197,52 @@ FCE = {x /x ∈ E AND x ∉ F} ONLY WHEN F IS A SUBSET OF E

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    Symentrical difference

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    Symentrical difference

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    E Δ F = (E - F) ∪ (F - E) ; = (E ∪ F) - (E ∩ F)

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    Proprieties :

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    Proprieties :

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    Let E,F and G be 3 sets. We have :

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    Commutativity:

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    Commutativity:

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    E ∩ F = F ∩ E E ∪ F = F ∪ E

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    Associativity:

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    E ∩ (F ∩ G) = (E ∩ F) ∩ G E ∪ (F ∪ G) = (E ∪ F) ∪ G

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    Distributivity:

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    E ∩ (F ∪ G) = (E ∩ F) ∪ (E ∩ G) E ∪ (F ∩ G) = (E ∪ F) ∩ (E ∪ G)

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    Lois de Morgan:

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    Lois de Morgan:

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    If E ⊂ G and F ⊂ G ;

    @@ -1252,33 +1252,33 @@ If E ⊂ G and F ⊂ G ;

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    An other one:

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    An other one:

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    E - (F ∩ G) = (E-F) ∪ (E-G) ; E - (F ∪ G) = (E-F) ∩ (E-G)

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    An other one:

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    An other one:

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    E ∩ ∅ = ∅ ; E ∪ ∅ = E

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    And an other one:

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    And an other one:

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    E ∩ (F Δ G) = (E ∩ F) Δ (E ∩ G)

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    And the last one:

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    And the last one:

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    E Δ ∅ = E ; E Δ E = ∅

    @@ -1289,7 +1289,7 @@ E Δ ∅ = E ; E Δ E = ∅

    Author: Crystal

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    Created: 2023-10-11 Wed 19:04

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    Created: 2023-10-13 Fri 16:58

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