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The two most popular dialects of Lisp are Scheme and Common Lisp. This appendix, which assumes that you have finished the rest of this book, describes the most important differences between Scheme and Common Lisp so that you will be able to use Common Lisp if you need to. Common Lisp is the most popular language among Artificial Intelligence researchers, so AI courses often use Common Lisp.
Since the beginning of Lisp, many versions of the language were developed. Each dialect reflected different ideas about the most important capabilities to include in the language. This diversity made Lisp an exciting arena for research, but it also meant that a Lisp program written for one dialect couldn't be used elsewhere.
In 1984, a group of Lisp developers decided to define a version of Lisp that would combine the capabilities of all their favorite dialects, so that in the future they would all use the same language; thus the name "Common" Lisp. Common Lisp was not the first attempt at a universal Lisp dialect, but it was more successful than earlier efforts. In 1985 a revision of the language was begun under the aegis of ANSI, the American National Standards Institute. This ANSI sponsorship gave Common Lisp an official status that has contributed to its growing acceptance.
Since Common Lisp was designed by combining the capabilities of many earlier
dialects, it's an enormous language with nearly 1000 primitives, including
versions of several programs in this book. There is a primitive sort
procedure, a procedure like number-name
that spells numbers in
English, and a substitute
procedure identical to the one you wrote in
an exercise, to name a few.
If you're writing your own programs in Common Lisp, you can ignore all the extra features and just use the capabilities you already know from Scheme. If you're trying to read someone else's Common Lisp program, we expect that you will have to look up many primitive procedures in a reference manual.
One minor difference between Scheme and Common Lisp is in the way procedures are defined. In Common Lisp,
(defun square (x) (* x x))
means the same as Scheme's
(define (square x) (* x x))
In Scheme, define
is used both for procedures and for variables whose
values aren't procedures. In Common Lisp, procedures are given names by a
mechanism separate from the general variable mechanism; defun
is only
for procedures. To define a variable, use defvar
:
common-lisp> (defvar x 6) 6 common-lisp> x 6
In Common Lisp, defvar
returns the name of the variable you
define. If a variable has already been defined, defvar
will not
change its value; for that you must use setq
.
In Common Lisp, names of predicate procedures end in a "p
" (for
"predicate") instead of a question mark. Unfortunately, this convention
isn't followed strictly. For example, Common Lisp's version of the null?
predicate is just "null
," not "nullp
."
We've mentioned that Scheme doesn't really have words and
sentences built in; neither does Common Lisp. So none of the following
procedures have Common Lisp equivalents: accumulate
, appearances
, before?
, bf
, bl
, butfirst
, butlast
, count
, empty?
, every
, first
, item
,
keep
, last
, member?
, se
, sentence
, word
,
and word?
. (Common Lisp does have lists, though, and list-related
procedures such as map
, reduce
, append
, and so on do
have equivalents.)
Common Lisp doesn't have the Boolean values #t
and #f
.
Instead, it has a single false value, nil
, which is also the empty
list.
common-lisp> (= 2 3) NIL common-lisp> (cdr '(one-word-list)) NIL common-lisp> '() NIL
Nil
is a strange beast in Common Lisp. It isn't a variable with the
empty list as its value; it's a special self-evaluating symbol. There is
also t
, a self-evaluating symbol with a true value.
common-lisp> 'nil NIL common-lisp> nil NIL common-lisp> t T
Like Scheme, Common Lisp treats every non-false (i.e., non-nil
) value
as true. But be careful; in Common Lisp
common-lisp> (if (cdr '(one-word-list)) 'yes 'no)
has the value NO
, because the empty list is nil
.
In Common Lisp's cond
, there is no equivalent to else
; Common
Lisp programmers instead use t
as the condition for their last clause,
like this:
(defun sign (n) (cond ((> n 0) 'positive) ((= n 0) 'zero) (t 'negative)))
Common Lisp's mechanism for dealing with files is trivially different from Scheme's. What Scheme calls "ports," Common Lisp calls "streams." Also, there is only one procedure for opening streams; the direction is specified this way:
common-lisp> (defvar out-stream (open "outfile" :direction :output)) #<OUTPUT STREAM "outfile"> common-lisp> (close out-stream) T common-lisp> (defvar in-stream (open "infile" :direction :input)) #<INPUT STREAM "infile"> common-lisp> (close in-stream) T
Note that the close
procedure closes both input streams and
output streams.
To read
from an input stream, you must invoke read
with three
arguments:
common-lisp> (read stream nil anything)
The nil
indicates that reaching the end of the file should
not be an error. If read
does reach the end of the file, instead of
returning a special end-of-file object it returns its third argument.
It's possible to choose any value as the indicator for reaching the end
of the file:
(let ((next (read stream nil 'xyzzy))) (if (equalp next 'xyzzy) 'done (do-something next)))
It's important to choose an end-of-file indicator that couldn't otherwise appear as a value in the file.
In Common Lisp, vectors are just a special case of the multidimensional array data type that you invented in Exercise 23.15. There are quite a few differences between Common Lisp arrays and Scheme vectors, none very difficult, but too numerous to describe here. If you need to use arrays, read about them in a Common Lisp book.
Other than the word and sentence procedures, here is a table of the Scheme primitives from the table on page funlist that have different names, slightly different behavior, or do not exist at all in Common Lisp. Scheme procedures not in this list (other than the word and sentence ones) can be used identically in Common Lisp.
Scheme | Common Lisp |
---|---|
align
| Common Lisp's format primitive has a similar purpose
|
begin
| progn
|
boolean?
| Doesn't exist; see the section in this appendix about true and false values. |
c...r
| The same, but (c...r nil) is nil instead
of an error.
|
children
| You can use our version from Chapter 18. |
close-...-port
| close
|
close-all-ports
| Doesn't exist. |
cond
| The same, except for else ; use t instead.
|
datum
| You can use our version from Chapter 18. |
define
| Either defun , for procedure, or
defvar , otherwise.
|
display
| princ
|
eof-object?
| See the section on files. |
equal?
| equalp
|
even?
| evenp
|
filter
| remove-if-not
|
for-each
| mapc
|
integer?
| integerp
|
lambda
| Discussed later in this appendix. |
list?
| listp , except that listp also returns true
for improper lists.
|
list-ref
| nth , except that the arguments come in reverse order.
|
list->vector
| See the section about arrays. |
make-node
| You can use our version from Chapter 18. |
make-vector
| See the section about arrays. |
map
| mapcar
|
newline
| terpri
|
null?
| null
|
number?
| numberp
|
odd?
| oddp
|
open-...-file
| See the section on files. |
procedure?
| functionp
|
quotient
| truncate
|
read
| Identical except for end of file. See the section on files. |
read-line
| Doesn't exist. (Common Lisp's read-line is like our
read-string .)
|
read-string
| read-line
|
reduce
| The same, but computes (f (f a b) c) instead of
(f a (f b c))
|
remainder
| rem
|
repeated
| Doesn't exist. |
show
| Doesn't exist but easy to write.
|
show-line
| Doesn't exist.
|
vector- anything
| See the section about arrays. |
write
| prin1
|
All of the differences noted in this table are fairly minor ones, in the sense that the translation needed to account for these differences requires little more than renaming. There is one major conceptual difference between the two languages, however, in the way they treat names of procedures. Common Lisp allows a procedure and a variable to have the same name. For example, the program
(defun three-copies (list) (list list list list))
is perfectly legal.
common-lisp> (three-copies '(drive my car)) ((DRIVE MY CAR) (DRIVE MY CAR) (DRIVE MY CAR))
How can Common Lisp tell that one of the list
s means the primitive
procedure, but the other ones mean the formal parameter? Symbols in the
first position in a list (right after an open parenthesis) are taken
to be names of globally defined procedures.
In Chapter 7 we introduced the image of a blackboard with all the
global variables written on it, which all the Scheme little people can see.
In Common Lisp, there are two blackboards: one for global
variables, just as in Scheme, and another one for procedures. The procedure
blackboard contains the primitive procedures and the procedures you define
with defun
. Names in the first position of an expression are looked
up on the procedure blackboard.
Therefore, the names of procedures are not variables and cannot be used as actual argument expressions:
common-lisp> (sqrt 144) 12 common-lisp> (mapcar sqrt '(9 16 25 36)) ERROR: The variable SQRT is unbound.
(Common Lisp's equivalent of map
is named mapcar
.)
How, then, do you tell Common Lisp that you want to use the procedure named
sqrt
as data? You must use the function
special
form.[1]
common-lisp> (function sqrt) #<PROCEDURE> common-lisp> (mapcar (function sqrt) '(9 16 25 36)) (3 4 5 6)
Function
's job is to look up names on the procedure
blackboard. (Function
actually has a more general definition, as
you'll see in a few paragraphs.)
Lambda
In Common Lisp, as in Scheme, procedures can be named or unnamed. Just as
procedure names in Common Lisp are meaningful only in certain contexts, so
are lambda
expressions. They make sense at the beginning of an
expression:
common-lisp> ((lambda (x) (* x x)) 4) 16
or as the argument to function
:
common-lisp> (function (lambda (x) (* x x))) #<PROCEDURE> common-lisp> (mapcar (function (lambda (x) (* x x))) '(3 4 5 6)) (9 16 25 36)
but they're meaningless on their own:
common-lisp> (lambda (x) (* x x)) ERROR: LAMBDA is not a function common-lisp> (mapcar (lambda (x) (* x x)) '(3 4 5 6)) ERROR: LAMBDA is not a function
Function
The official rule is that function
returns the "functional
interpretation" of its argument. If the argument is a symbol, that means
looking up the procedure associated with that name. If the argument is a
lambda
expression, it means creating a new procedure. Function
uses the same rule that's used to interpret the first element of a procedure
invocation.
Since function
is a very commonly used special form, it has an
abbreviation:
common-lisp> (mapcar #'(lambda (x) (* x x)) '(3 4 5 6)) (9 16 25 36) common-lisp> (mapcar #'cdr '((hey jude) (eleanor rigby) (yes it is))) ((JUDE) (RIGBY) (IT IS))
Don't confuse
#'(lambda (x) (* x x))
with
'#(lambda (x) (* x x))
The first of these is a function that squares its argument; the second is an array containing three elements.
It's unfortunate that the abbreviation for function
contains a single
quote mark, because the job of function
is nothing like the job of
quote
. You'll just have to get used to the "hashquote" notation.
Think about this attempted translation of the map
procedure:
(defun map (fn lst) ;; wrong! (if (null lst) '() (cons (fn (car lst)) (map fn (cdr lst)))))
(In Common Lisp, null
is one of the predicates whose names
don't end in "p." Otherwise, this is the same program we showed you in
Chapter 19, except for the defun
, of course.)
According to our rule about names in the front of a list, this procedure doesn't work. Think about what happens when we say
(map #'square '(1 2 3 4 5))
According to the substitution model, the parameters fn
and
lst
are replaced in the body with #'square
and '(1 2 3 4 5)
. But Common Lisp makes an exception for the first
element of a compound expression. It uses the procedure blackboard instead
of substitution:
(if (null '(1 2 3 4 5)) '() (cons (fn (car '(1 2 3 4 5)) (map #'square (cdr '(1 2 3 4 5))))))
Note that one of the appearances of fn
was left unchanged.
Since there is no global procedure named fn
, this program will produce
an error:
common-lisp> (map #'square '(1 2 3 4 5)) ERROR: FN is not a procedure.
How, then, do you write higher-order procedures in Common Lisp? The answer is
that you must use funcall
:
(defun map (fn lst) (if (null lst) '() (cons (funcall fn (car lst)) (map fn (cdr lst)))))
Funcall
takes one or more arguments. The first is a
procedure and the rest are arguments for that procedure. It applies that
procedure to the given arguments.[2] Since fn
is no longer
at the beginning of a compound expression, the corresponding argument,
#'square
, is substituted for it.
[2] This is a lot like apply
,
you may have noticed. Look at the difference:
common-lisp> (funcall #'+ 1 2 3) 6 common-lisp> (apply #'+ '(1 2 3)) 6
In the first case, each argument to +
is a separate argument to funcall
. In the second case, a list of the arguments to +
is a
single argument to apply
. Apply
always takes exactly two
arguments, the procedure and the argument list.
Brian Harvey,
bh@cs.berkeley.edu