From 8f049ad6d4ffab5bd7b758b7133f5fae7c29e7bb Mon Sep 17 00:00:00 2001
From: Andrew
Under what circumstance shall mathematical logic be ``trusted'' in physics?
How is it possible to know anything in physics? +
How is it possible to know anything in physics? Experiments can be inaccurate or conducted wrongly or can be affected by physical properties completely unknown to us, and mathematical proof can be erroneous because of systematic flaws and/or false assumptions about the representation of physical entities in math.
Gödel's theorems only tell us that there are true -statements that we cannot prove, and there may be +
Gödel's theorems only tell us that there are true +statements that we cannot prove, and there may be inconsistencies. My intuition suggests that these statements and inconsistencies would be in the highly theoretical realm of math, which if accurately identified and are avoided in physics, would not pose a @@ -155,20 +155,20 @@ threat to applied mathematics in physics.
However, it shall be noted that any single inconsistency may be abused to prove any statement, if consistencies were to be found in math: Suppose that we know a statement A (i. e. physics is squishy) is both -true and false. Thus, A = 1 -and A = 0 are both true. Then, -take a random statement B +class="math inline">A (i. e. physics is squishy) is both +true and false. Thus, A = 1 +and A = 0 are both true. Then, +take a random statement B (let's say ``my friend likes humanities''). Thus we have A + B = 1 where A + B = 1 where + is a boolean ``or'' operator because A = 1 and 1 + x = 1 (x is any statement). But then -because A = 0, thus 0 + B = 1, which means that B must be 1 (if B is zero, then A = 1 and 1 + x = 1 (x is any statement). But then +because A = 0, thus 0 + B = 1, which means that B must be 1 (if B is zero, then 0 + 0 = 0). Thus, if we can prove that ``physics is squishy'' and ``physics is not squishy'' (without differences in definition), then we can literally prove that ``my friend likes -- cgit 1.4.1-2-gfad0