blob: 7c8661bb7fb67800fb76db63208c65a7fb897a6f (
plain) (
tree)
|
|
# This module is inspired by Python's `ntpath.py` module.
import std/[
strutils,
]
# Adapted `splitdrive` function from the following commits in Python source
# code:
# 5a607a3ee5e81bdcef3f886f9d20c1376a533df4 (2009): Initial UNC handling (by Mark Hammond)
# 2ba0fd5767577954f331ecbd53596cd8035d7186 (2022): Support for "UNC"-device paths (by Barney Gale)
#
# FAQ: Why use `strip` below? `\\?\UNC` is the start of a "UNC symbolic link",
# which is a special UNC form. Running `strip` differentiates `\\?\UNC\` (a UNC
# symbolic link) from e.g. `\\?\UNCD` (UNCD is the server in the UNC path).
func splitDrive*(p: string): tuple[drive, path: string] =
## Splits a Windows path into a drive and path part. The drive can be e.g.
## `C:`. It can also be a UNC path (`\\server\drive\path`).
##
## The equivalent `splitDrive` for POSIX systems always returns empty drive.
## Therefore this proc is only necessary on DOS-like file systems (together
## with Nim's `doslikeFileSystem` conditional variable).
##
## This proc's use case is to extract `path` such that it can be manipulated
## like a POSIX path.
runnableExamples:
doAssert splitDrive("C:") == ("C:", "")
doAssert splitDrive(r"C:\") == (r"C:", r"\")
doAssert splitDrive(r"\\server\drive\foo\bar") == (r"\\server\drive", r"\foo\bar")
doAssert splitDrive(r"\\?\UNC\server\share\dir") == (r"\\?\UNC\server\share", r"\dir")
result = ("", p)
if p.len < 2:
return
const sep = '\\'
let normp = p.replace('/', sep)
if p.len > 2 and normp[0] == sep and normp[1] == sep and normp[2] != sep:
# is a UNC path:
# vvvvvvvvvvvvvvvvvvvv drive letter or UNC path
# \\machine\mountpoint\directory\etc\...
# directory ^^^^^^^^^^^^^^^
let start = block:
const unc = "\\\\?\\UNC" # Length is 7
let idx = min(8, normp.len)
if unc == normp[0..<idx].strip(chars = {sep}, leading = false).toUpperAscii:
8
else:
2
let index = normp.find(sep, start)
if index == -1:
return
var index2 = normp.find(sep, index + 1)
# a UNC path can't have two slashes in a row (after the initial two)
if index2 == index + 1:
return
if index2 == -1:
index2 = p.len
return (p[0..<index2], p[index2..^1])
if p[1] == ':':
return (p[0..1], p[2..^1])
|