diff options
author | Arne Döring <arne.doering@gmx.net> | 2018-12-07 16:21:50 +0100 |
---|---|---|
committer | Arne Döring <arne.doering@gmx.net> | 2018-12-07 16:21:50 +0100 |
commit | 43ea41bdf4626831116568b0b19e665a41c3f98b (patch) | |
tree | cfeec7b3ccb9d77b273229d335bde237ff6fd7df | |
parent | 1711a60f7b3968285bb753b2e98bfc4638d32a44 (diff) | |
download | Nim-43ea41bdf4626831116568b0b19e665a41c3f98b.tar.gz |
added lib/std/diff.nim
-rw-r--r-- | lib/std/diff.nim | 463 |
1 files changed, 463 insertions, 0 deletions
diff --git a/lib/std/diff.nim b/lib/std/diff.nim new file mode 100644 index 000000000..940b5888d --- /dev/null +++ b/lib/std/diff.nim @@ -0,0 +1,463 @@ + +## This Class implements the Difference Algorithm published in +## "An O(ND) Difference Algorithm and its Variations" by Eugene Myers +## Algorithmica Vol. 1 No. 2, 1986, p 251. +## +## There are many C, Java, Lisp implementations public available but they all seem to come +## from the same source (diffutils) that is under the (unfree) GNU public License +## and cannot be reused as a sourcecode for a commercial application. +## There are very old C implementations that use other (worse) algorithms. +## Microsoft also published sourcecode of a diff-tool (windiff) that uses some tree data. +## Also, a direct transfer from a C source to C# is not easy because there is a lot of pointer +## arithmetic in the typical C solutions and i need a managed solution. +## These are the reasons why I implemented the original published algorithm from the scratch and +## make it avaliable without the GNU license limitations. +## I do not need a high performance diff tool because it is used only sometimes. +## I will do some performace tweaking when needed. +## +## The algorithm itself is comparing 2 arrays of numbers so when comparing 2 text documents +## each line is converted into a (hash) number. See diffText(). +## +## Some chages to the original algorithm: +## The original algorithm was described using a recursive approach and comparing zero indexed arrays. +## Extracting sub-arrays and rejoining them is very performance and memory intensive so the same +## (readonly) data arrays are passed arround together with their lower and upper bounds. +## This circumstance makes the lcs and sms functions more complicate. +## I added some code to the lcs function to get a fast response on sub-arrays that are identical, +## completely deleted or inserted. +## +## The result from a comparisation is stored in 2 arrays that flag for modified (deleted or inserted) +## lines in the 2 data arrays. These bits are then analysed to produce a array of Item objects. +## +## Further possible optimizations: +## (first rule: don't do it; second: don't do it yet) +## The arrays dataA and dataB are passed as parameters, but are never changed after the creation +## so they can be members of the class to avoid the paramter overhead. +## In sms is a lot of boundary arithmetic in the for-D and for-k loops that can be done by increment +## and decrement of local variables. +## The downVector and upVector arrays are alywas created and destroyed each time the sms gets called. +## It is possible to reuse tehm when transfering them to members of the class. +## See TODO: hints. +## +## diff.cs: A port of the algorythm to C# +## Copyright (c) by Matthias Hertel, http://www.mathertel.de +## This work is licensed under a BSD style license. See http://www.mathertel.de/License.aspx +## +## Changes: +## 2002.09.20 There was a "hang" in some situations. +## Now I undestand a little bit more of the sms algorithm. +## There have been overlapping boxes; that where analyzed partial differently. +## One return-point is enough. +## A assertion was added in createDiffs when in debug-mode, that counts the number of equal (no modified) lines in both arrays. +## They must be identical. +## +## 2003.02.07 Out of bounds error in the Up/Down vector arrays in some situations. +## The two vetors are now accessed using different offsets that are adjusted using the start k-Line. +## A test case is added. +## +## 2006.03.05 Some documentation and a direct Diff entry point. +## +## 2006.03.08 Refactored the API to static methods on the Diff class to make usage simpler. +## 2006.03.10 using the standard Debug class for self-test now. +## compile with: csc /target:exe /out:diffTest.exe /d:DEBUG /d:TRACE /d:SELFTEST Diff.cs +## 2007.01.06 license agreement changed to a BSD style license. +## 2007.06.03 added the optimize method. +## 2007.09.23 upVector and downVector optimization by Jan Stoklasa (). +## 2008.05.31 Adjusted the testing code that failed because of the optimize method (not a bug in the diff algorithm). +## 2008.10.08 Fixing a test case and adding a new test case. +## 2018.12.07 Port to Nim. + +import tables, strutils + +type + Item* = object + startA*: int ## Start Line number in Data A. + startB*: int ## Start Line number in Data B. + deletedA*: int ## Number of changes in Data A. + insertedB*: int ## Number of changes in Data B. + + DiffData = object + ## Data on one input file being compared. + len: int ## Number of elements (lines). + data: seq[int] ## Buffer of numbers that will be compared. + modified: seq[bool] ## Array of booleans that flag for modified + ## data. This is the result of the diff. + ## This means deletedA in the first Data or + ## inserted in the second Data. + + SMSRD = object + x,y: int + +proc newDiffData(initData: seq[int]): DiffData = + ## Initialize the Diff-Data buffer. + result.len = initData.len + result.data = initData + result.modified = newSeq[bool](result.len + 2) + +proc diffCodes(aText: string; h: var Table[string,int]): seq[int] = + ## This function converts all textlines of the text into unique numbers for every unique textline + ## so further work can work only with simple numbers. + ## ``aText`` the input text + ## ``h`` This extern initialized hashtable is used for storing all ever used textlines. + ## ``trimSpace`` ignore leading and trailing space characters + ## Returns a array of integers. + + # get all codes of the text + var lastUsedCode = h.len + var codes = newSeq[int]() + for s in aText.splitLines: + if h.contains s: + codes.add h[s] + else: + inc lastUsedCode + h[s] = lastUsedCode + codes.add lastUsedCode + + return codes + +proc optimize(data: var DiffData): void = + ## If a sequence of modified lines starts with a line that contains the same content + ## as the line that appends the changes, the difference sequence is modified so that the + ## appended line and not the starting line is marked as modified. + ## This leads to more readable diff sequences when comparing text files. + ## ``data`` A Diff data buffer containing the identified changes. + + var startPos, endPos: int + startPos = 0 + + while startPos < data.len: + while (startPos < data.len) and (data.modified[startPos] == false): + inc startPos + endPos = startPos + while (endPos < data.len) and (data.modified[endPos] == true): + inc endPos + + if (endPos < data.len) and (data.data[startPos] == data.data[endPos]): + data.modified[startPos] = false + data.modified[endPos] = true + else: + startPos = endPos + +proc sms(dataA: var DiffData; lowerA, upperA: int; dataB: DiffData; lowerB, upperB: int; + downVector, upVector: var openArray[int]): SMSRD = + ## This is the algorithm to find the Shortest Middle Snake (sms). + ## ``dataA`` sequence A + ## ``lowerA`` lower bound of the actual range in dataA + ## ``upperA`` upper bound of the actual range in dataA (exclusive) + ## ``dataB`` sequence B + ## ``lowerB`` lower bound of the actual range in dataB + ## ``upperB`` upper bound of the actual range in dataB (exclusive) + ## ``downVector`` a vector for the (0,0) to (x,y) search. Passed as a parameter for speed reasons. + ## ``upVector`` a vector for the (u,v) to (N,M) search. Passed as a parameter for speed reasons. + ## Returns a MiddleSnakeData record containing x,y and u,v. + + let max: int = dataA.len + dataB.len + 1 + + let downK = lowerA - lowerB; # the k-line to start the forward search + let upK = upperA - upperB; # the k-line to start the reverse search + + let delta = (upperA - lowerA) - (upperB - lowerB) + let oddDelta = (delta and 1) != 0 + + # The vectors in the publication accepts negative indexes. the vectors implemented here are 0-based + # and are access using a specific offset: upOffset upVector and downOffset for downVector + let downOffset = max - downK + let upOffset = max - upK + + let maxD = ((upperA - lowerA + upperB - lowerB) div 2) + 1 + + # Debug.Write(2, "sms", String.Format("Search the box: A[{0}-{1}] to B[{2}-{3}]", lowerA, upperA, lowerB, upperB)) + + # init vectors + downVector[downOffset + downK + 1] = lowerA + upVector[upOffset + upK - 1] = upperA + + for D in 0 .. maxD: + + # Extend the forward path. + + for k in countUp(downK - D, downK + D, 2): + # Debug.Write(0, "sms", "extend forward path " + k.ToString()) + + # find the only or better starting point + var x, y: int + if k == downK - D: + x = downVector[downOffset + k + 1]; # down + else: + x = downVector[downOffset + k - 1] + 1; # a step to the right + if (k < downK + D) and (downVector[downOffset + k + 1] >= x): + x = downVector[downOffset + k + 1]; # down + + y = x - k + + # find the end of the furthest reaching forward D-path in diagonal k. + while (x < upperA) and (y < upperB) and (dataA.data[x] == dataB.data[y]): + inc x + inc y + + downVector[downOffset + k] = x + + # overlap ? + if oddDelta and (upK - D < k) and (k < upK + D): + if upVector[upOffset + k] <= downVector[downOffset + k]: + result.x = downVector[downOffset + k] + result.y = downVector[downOffset + k] - k + return + + # Extend the reverse path. + for k in countUp(upK - D, upK + D, 2): + # Debug.Write(0, "sms", "extend reverse path " + k.ToString()) + + # find the only or better starting point + var x, y: int + if k == upK + D: + x = upVector[upOffset + k - 1]; # up + else: + x = upVector[upOffset + k + 1] - 1; # left + if (k > upK - D) and (upVector[upOffset + k - 1] < x): + x = upVector[upOffset + k - 1]; # up + # if + y = x - k + + while (x > lowerA) and (y > lowerB) and (dataA.data[x - 1] == dataB.data[y - 1]): + dec x + dec y + + upVector[upOffset + k] = x + + # overlap ? + if (not oddDelta) and (downK - D <= k) and (k <= downK + D): + if upVector[upOffset + k] <= downVector[downOffset + k]: + result.x = downVector[downOffset + k] + result.y = downVector[downOffset + k] - k + return + + assert false, "the algorithm should never come here." + +proc lcs(dataA: var DiffData; lowerA, upperA: int; dataB: var DiffData; lowerB, upperB: int; downVector, upVector: var openArray[int]): void = + ## This is the divide-and-conquer implementation of the longes common-subsequence (lcs) + ## algorithm. + ## The published algorithm passes recursively parts of the A and B sequences. + ## To avoid copying these arrays the lower and upper bounds are passed while the sequences stay constant. + ## ``dataA`` sequence A + ## ``lowerA`` lower bound of the actual range in dataA + ## ``upperA`` upper bound of the actual range in dataA (exclusive) + ## ``dataB`` sequence B + ## ``lowerB`` lower bound of the actual range in dataB + ## ``upperB`` upper bound of the actual range in dataB (exclusive) + ## ``downVector`` a vector for the (0,0) to (x,y) search. Passed as a parameter for speed reasons. + ## ``upVector`` a vector for the (u,v) to (N,M) search. Passed as a parameter for speed reasons. + # make mutable copy + var lowerA = lowerA + var lowerB = lowerB + var upperA = upperA + var upperB = upperB + + # Debug.Write(2, "lcs", String.Format("Analyse the box: A[{0}-{1}] to B[{2}-{3}]", lowerA, upperA, lowerB, upperB)) + + # Fast walkthrough equal lines at the start + while lowerA < upperA and lowerB < upperB and dataA.data[lowerA] == dataB.data[lowerB]: + inc lowerA + inc lowerB + + # Fast walkthrough equal lines at the end + while lowerA < upperA and lowerB < upperB and dataA.data[upperA - 1] == dataB.data[upperB - 1]: + dec upperA + dec upperB + + if lowerA == upperA: + # mark as inserted lines. + while lowerB < upperB: + dataB.modified[lowerB] = true + inc lowerB + + elif lowerB == upperB: + # mark as deleted lines. + while lowerA < upperA: + dataA.modified[lowerA] = true + inc lowerA + + else: + # Find the middle snakea and length of an optimal path for A and B + let smsrd = sms(dataA, lowerA, upperA, dataB, lowerB, upperB, downVector, upVector) + # Debug.Write(2, "MiddleSnakeData", String.Format("{0},{1}", smsrd.x, smsrd.y)) + + # The path is from LowerX to (x,y) and (x,y) to UpperX + lcs(dataA, lowerA, smsrd.x, dataB, lowerB, smsrd.y, downVector, upVector) + lcs(dataA, smsrd.x, upperA, dataB, smsrd.y, upperB, downVector, upVector) # 2002.09.20: no need for 2 points + +# lcs() + +proc createDiffs(dataA, dataB: DiffData): seq[Item] = + ## Scan the tables of which lines are inserted and deleted, + ## producing an edit script in forward order. + + var startA: int + var startB: int + var lineA: int + var lineB: int + + while lineA < dataA.len or lineB < dataB.len: + if (lineA < dataA.len) and (not dataA.modified[lineA]) and + (lineB < dataB.len) and (not dataB.modified[lineB]): + # equal lines + inc lineA + inc lineB + else: + # maybe deleted and/or inserted lines + startA = lineA + startB = lineB + + while lineA < dataA.len and (lineB >= dataB.len or dataA.modified[lineA]): + # while (lineA < dataA.len and dataA.modified[lineA]) + inc lineA + + while lineB < dataB.len and (lineA >= dataA.len or dataB.modified[lineB]): + # while (lineB < dataB.len and dataB.modified[lineB]) + inc lineB + + if (startA < lineA) or (startB < lineB): + # store a new difference-item + var aItem: Item + aItem.startA = startA + aItem.startB = startB + aItem.deletedA = lineA - startA + aItem.insertedB = lineB - startB + result.add aItem + + +proc diffInt*(arrayA, arrayB: openArray[int]): seq[Item] = + ## Find the difference in 2 arrays of integers. + ## ``arrayA`` A-version of the numbers (usualy the old one) + ## ``arrayB`` B-version of the numbers (usualy the new one) + ## Returns a array of Items that describe the differences. + + # The A-Version of the data (original data) to be compared. + var dataA = newDiffData(@arrayA) + + # The B-Version of the data (modified data) to be compared. + var dataB = newDiffData(@arrayB) + + let max = dataA.len + dataB.len + 1 + ## vector for the (0,0) to (x,y) search + var downVector = newSeq[int](2 * max + 2) + ## vector for the (u,v) to (N,M) search + var upVector = newSeq[int](2 * max + 2) + + lcs(dataA, 0, dataA.len, dataB, 0, dataB.len, downVector, upVector) + return createDiffs(dataA, dataB) + +proc diffText*(textA,textB: string): seq[Item] = + ## Find the difference in 2 text documents, comparing by textlines. + ## The algorithm itself is comparing 2 arrays of numbers so when comparing 2 text documents + ## each line is converted into a (hash) number. This hash-value is computed by storing all + ## textlines into a common hashtable so i can find dublicates in there, and generating a + ## new number each time a new textline is inserted. + ## ``TextA`` A-version of the text (usualy the old one) + ## ``TextB`` B-version of the text (usualy the new one) + ## ``trimSpace`` When set to true, all leading and trailing whitespace characters are stripped out before the comparation is done. + ## ``ignoreSpace`` When set to true, all whitespace characters are converted to a single space character before the comparation is done. + ## ``ignoreCase`` When set to true, all characters are converted to their lowercase equivivalence before the comparation is done. + ## Returns a seq of Items that describe the differences. + + # prepare the input-text and convert to comparable numbers. + var h = initTable[string,int]() # TextA.len + TextB.len <- probably wrong initial size + # The A-Version of the data (original data) to be compared. + var dataA = newDiffData(diffCodes(textA, h)) + + # The B-Version of the data (modified data) to be compared. + var dataB = newDiffData(diffCodes(textB, h)) + + h.clear # free up hashtable memory (maybe) + + let max = dataA.len + dataB.len + 1 + ## vector for the (0,0) to (x,y) search + var downVector = newSeq[int](2 * max + 2) + ## vector for the (u,v) to (N,M) search + var upVector = newSeq[int](2 * max + 2) + + lcs(dataA, 0, dataA.len, dataB, 0, dataB.len, downVector, upVector) + + optimize(dataA) + optimize(dataB) + return createDiffs(dataA, dataB) + +when isMainModule: + + proc testHelper(f: seq[Item]): string = + for it in f: + result.add( + $it.deletedA & "." & $it.insertedB & "." & $it.startA & "." & $it.startB & "*" + ) + + proc main(): void = + var a, b: string + + stdout.writeLine("Diff Self Test...") + + # test all changes + a = "a,b,c,d,e,f,g,h,i,j,k,l".replace(',', '\n') + b = "0,1,2,3,4,5,6,7,8,9".replace(',', '\n') + assert(testHelper(diffText(a, b)) == + "12.10.0.0*", + "all-changes test failed.") + stdout.writeLine("all-changes test passed.") + # test all same + a = "a,b,c,d,e,f,g,h,i,j,k,l".replace(',', '\n') + b = a + assert(testHelper(diffText(a, b)) == + "", + "all-same test failed.") + stdout.writeLine("all-same test passed.") + + # test snake + a = "a,b,c,d,e,f".replace(',', '\n') + b = "b,c,d,e,f,x".replace(',', '\n') + assert(testHelper(diffText(a, b)) == + "1.0.0.0*0.1.6.5*", + "snake test failed.") + stdout.writeLine("snake test passed.") + + # 2002.09.20 - repro + a = "c1,a,c2,b,c,d,e,g,h,i,j,c3,k,l".replace(',', '\n') + b = "C1,a,C2,b,c,d,e,I1,e,g,h,i,j,C3,k,I2,l".replace(',', '\n') + assert(testHelper(diffText(a, b)) == + "1.1.0.0*1.1.2.2*0.2.7.7*1.1.11.13*0.1.13.15*", + "repro20020920 test failed.") + stdout.writeLine("repro20020920 test passed.") + + # 2003.02.07 - repro + a = "F".replace(',', '\n') + b = "0,F,1,2,3,4,5,6,7".replace(',', '\n') + assert(testHelper(diffText(a, b)) == + "0.1.0.0*0.7.1.2*", + "repro20030207 test failed.") + stdout.writeLine("repro20030207 test passed.") + + # Muegel - repro + a = "HELLO\nWORLD" + b = "\n\nhello\n\n\n\nworld\n" + assert(testHelper(diffText(a, b)) == + "2.8.0.0*", + "repro20030409 test failed.") + stdout.writeLine("repro20030409 test passed.") + + # test some differences + a = "a,b,-,c,d,e,f,f".replace(',', '\n') + b = "a,b,x,c,e,f".replace(',', '\n') + assert(testHelper(diffText(a, b)) == + "1.1.2.2*1.0.4.4*1.0.7.6*", + "some-changes test failed.") + stdout.writeLine("some-changes test passed.") + + # test one change within long chain of repeats + a = "a,a,a,a,a,a,a,a,a,a".replace(',', '\n') + b = "a,a,a,a,-,a,a,a,a,a".replace(',', '\n') + assert(testHelper(diffText(a, b)) == + "0.1.4.4*1.0.9.10*", + "long chain of repeats test failed.") + + stdout.writeLine("End.") + stdout.flushFile + + main() |