diff options
Diffstat (limited to 'lib/system/strmantle.nim')
| -rw-r--r-- | lib/system/strmantle.nim | 49 |
1 files changed, 29 insertions, 20 deletions
diff --git a/lib/system/strmantle.nim b/lib/system/strmantle.nim index feaac7817..89046253b 100644 --- a/lib/system/strmantle.nim +++ b/lib/system/strmantle.nim @@ -17,12 +17,20 @@ proc cmpStrings(a, b: string): int {.inline, compilerproc.} = let blen = b.len let minlen = min(alen, blen) if minlen > 0: - result = c_memcmp(unsafeAddr a[0], unsafeAddr b[0], cast[csize_t](minlen)) + result = c_memcmp(unsafeAddr a[0], unsafeAddr b[0], cast[csize_t](minlen)).int if result == 0: result = alen - blen else: result = alen - blen +proc leStrings(a, b: string): bool {.inline, compilerproc.} = + # required by upcoming backends (NIR). + cmpStrings(a, b) <= 0 + +proc ltStrings(a, b: string): bool {.inline, compilerproc.} = + # required by upcoming backends (NIR). + cmpStrings(a, b) < 0 + proc eqStrings(a, b: string): bool {.inline, compilerproc.} = let alen = a.len let blen = b.len @@ -33,7 +41,7 @@ proc eqStrings(a, b: string): bool {.inline, compilerproc.} = proc hashString(s: string): int {.compilerproc.} = # the compiler needs exactly the same hash function! # this used to be used for efficient generation of string case statements - var h : uint = 0 + var h = 0'u for i in 0..len(s)-1: h = h + uint(s[i]) h = h + h shl 10 @@ -75,11 +83,11 @@ const 1e10, 1e11, 1e12, 1e13, 1e14, 1e15, 1e16, 1e17, 1e18, 1e19, 1e20, 1e21, 1e22] -when defined(nimHasInvariant): - {.push staticBoundChecks: off.} -proc nimParseBiggestFloat(s: string, number: var BiggestFloat, - start = 0): int {.compilerproc.} = +{.push staticBoundChecks: off.} + +proc nimParseBiggestFloat(s: openArray[char], number: var BiggestFloat, + ): int {.compilerproc.} = # This routine attempt to parse float that can parsed quickly. # i.e. whose integer part can fit inside a 53bits integer. # their real exponent must also be <= 22. If the float doesn't follow @@ -88,7 +96,7 @@ proc nimParseBiggestFloat(s: string, number: var BiggestFloat, # This avoid the problems of decimal character portability. # see: http://www.exploringbinary.com/fast-path-decimal-to-floating-point-conversion/ var - i = start + i = 0 sign = 1.0 kdigits, fdigits = 0 exponent = 0 @@ -111,7 +119,7 @@ proc nimParseBiggestFloat(s: string, number: var BiggestFloat, if s[i+2] == 'N' or s[i+2] == 'n': if i+3 >= s.len or s[i+3] notin IdentChars: number = NaN - return i+3 - start + return i+3 return 0 # Inf? @@ -120,7 +128,7 @@ proc nimParseBiggestFloat(s: string, number: var BiggestFloat, if s[i+2] == 'F' or s[i+2] == 'f': if i+3 >= s.len or s[i+3] notin IdentChars: number = Inf*sign - return i+3 - start + return i+3 return 0 if i < s.len and s[i] in {'0'..'9'}: @@ -154,8 +162,8 @@ proc nimParseBiggestFloat(s: string, number: var BiggestFloat, # if has no digits: return error if kdigits + fdigits <= 0 and - (i == start or # no char consumed (empty string). - (i == start + 1 and hasSign)): # or only '+' or '- + (i == 0 or # no char consumed (empty string). + (i == 1 and hasSign)): # or only '+' or '- return 0 if i+1 < s.len and s[i] in {'e', 'E'}: @@ -178,11 +186,13 @@ proc nimParseBiggestFloat(s: string, number: var BiggestFloat, # if exponent greater than can be represented: +/- zero or infinity if absExponent > 999: - if expNegative: + if integer == 0: + number = 0.0 + elif expNegative: number = 0.0*sign else: number = Inf*sign - return i - start + return i # if integer is representable in 53 bits: fast path # max fast path integer is 1<<53 - 1 or 8999999999999999 (16 digits) @@ -194,14 +204,14 @@ proc nimParseBiggestFloat(s: string, number: var BiggestFloat, number = sign * integer.float / powtens[absExponent] else: number = sign * integer.float * powtens[absExponent] - return i - start + return i # if exponent is greater try to fit extra exponent above 22 by multiplying # integer part is there is space left. let slop = 15 - kdigits - fdigits if absExponent <= 22 + slop and not expNegative: number = sign * integer.float * powtens[slop] * powtens[absExponent-slop] - return i - start + return i # if failed: slow path with strtod. var t: array[500, char] # flaviu says: 325 is the longest reasonable literal @@ -209,8 +219,8 @@ proc nimParseBiggestFloat(s: string, number: var BiggestFloat, let maxlen = t.high - "e+000".len # reserve enough space for exponent let endPos = i - result = endPos - start - i = start + result = endPos + i = 0 # re-parse without error checking, any error should be handled by the code above. if i < endPos and s[i] == '.': i.inc while i < endPos and s[i] in {'0'..'9','+','-'}: @@ -232,10 +242,9 @@ proc nimParseBiggestFloat(s: string, number: var BiggestFloat, t[ti-2] = ('0'.ord + absExponent mod 10).char absExponent = absExponent div 10 t[ti-3] = ('0'.ord + absExponent mod 10).char - number = c_strtod(addr t, nil) + number = c_strtod(cast[cstring](addr t), nil) -when defined(nimHasInvariant): - {.pop.} # staticBoundChecks +{.pop.} # staticBoundChecks proc nimBoolToStr(x: bool): string {.compilerRtl.} = return if x: "true" else: "false" |