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## add the first 10 numbers, and return the result in the exit code
#
# To run:
#   $ subx translate ex3.subx ex3
#   $ subx run ex3
# Expected result:
#   $ echo $?
#   55

== code
# instruction                     effective address                                                   operand     displacement    immediate
# op          subop               mod             rm32          base        index         scale       r32
# 1-3 bytes   3 bits              2 bits          3 bits        3 bits      3 bits        2 bits      2 bits      0/1/2/4 bytes   0/1/2/4 bytes
  # result: EBX = 0
  bb/copy                                                                                                                         0/imm32           # copy 0 to EBX
  # counter: ECX = 1
  b9/copy                                                                                                                         1/imm32           # copy 1 to ECX

$loop:
  # while (counter <= 10)
  81          7/subop/compare     3/mod/direct    1/rm32/ECX                                                                      0xa/imm32         # compare ECX, 10/imm
  7f/jump-if-greater  $exit/disp8
  # result += counter
  01/add                          3/mod/direct    3/rm32/EBX                                          1/r32/ECX                                     # add ECX to EBX
  # ++counter
  81          0/subop/add         3/mod/direct    1/rm32/ECX                                                                      1/imm32           # add 1 to ECX
  # loop
  eb/jump  $loop/disp8

$exit:
  # exit(EBX)
  b8/copy                                                                                                                         1/imm32           # copy 1 to EAX
  cd/syscall  0x80/imm8

# vim:ft=subx:nowrap