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58pre { line-height: 125%; }
td.linenos .normal { color: inherit; background-color: transparent; padding-left: 5px; padding-right: 5px; }
span.linenos { color: inherit; background-color: transparent; padding-left: 5px; padding-right: 5px; }
td.linenos .special { color: #000000; background-color: #ffffc0; padding-lefunit module Octans::WordSearch;
use Octans::Neighbors;
use Octans::RangeSearch;
# word-search walks the given grid & tries to find words in the
# dictionary. It walks in Depth-First manner (lookup Depth-First
# search).
sub word-search (
# @dict holds the dictionary. @puzzle holds the puzzle.
@dict, @puzzle,
# $y, $x is the position of the current cell, we have to follow
# this path. $str is the string we've looked up until now. If it's
# not passed then assume that we're starting at $y, $x and take
# @puzzle[$y][$x] as the string.
#
# $str should be passed in recursive calls, it's not required when
# $y, $x is the starting position.
Int $y, Int $x, $str? = @puzzle[$y][$x],
# @visited holds the positions that we've already visited.
@visited? is copy --> List
) is export {
# If @visited was not passed then mark the given cell as visited
# because it's the cell we're starting at.
@visited[$y][$x] = True unless @visited;
# neighbor block loops over the neighbors of $y, $x.
neighbor: for neighbors(@puzzle, $y, $x).List -> $pos {
# Move on to next neighbor if we've already visited this one.
next neighbor if @visited[$pos[0]][$pos[1]];
# Mark this cell as visited but only until we search this
# path. When moving to next neighbor, mark it False.
@visited[$pos[0]][$pos[1]] = True;
# $word is the string that we're going to lookup in the
# dictionary.
my Str $word = $str ~ @puzzle[$pos[0]][$pos[1]];
# range-starts-with returns a list of all words in the
# dictionary that start with $word.
with range-starts-with(@dict, $word) -> @list {
if @list.elems > 0 {
# If $word exist in the dictionary then it should be
# the first element in the list.
take @list[0], @visited if @list[0] eq $word;
# Continue on this path because there are 1 or more
# elements in @list which means we could find a word.
word-search(
# Don't pass the whole dictionary for next search.
# Words that start with "ab" will always be a
# subset of words that start with "a", so keeping
# this in mind we pass the output of last
# range-starts-with (@list).
@list, @puzzle, $pos[0], $pos[1], $word, @visited
);
}
}
# We're done looking up this path, mark this cell as False &
# move on to another neighbor.
@visited[$pos[0]][$pos[1]] = False;
}
}
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