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# range-starts-with returns a subset of given @dict list that start
# with $str. It should be faster than:
#
# @dict.grep: *.starts-with($str)
#
# @dict should be a sorted list of words. It performs binary lookup on
# the list.
sub range-starts-with(
@dict, Str $str --> List
) is export {
# $lower, $upper hold the lower and upper index of the range
# respectively.
my Int ($lower, $upper);
# Lookup the whole dictionary.
my Int ($start, $end) = (0, @dict.end);
# Loop until we end up on the lower index of range.
while $start < $end {
# Divide the list into 2 parts.
my Int $mid = ($start + $end) div 2;
# Check if $mid word is le (less than or equal to) $str. If
# true then discard the bottom end of the list, if not then
# discard the top end.
if $str le @dict[$mid].substr(0, $str.chars).lc {
$end = $mid;
} else {
$start = $mid + 1;
}
}
# Found the lower index.
$lower = $start;
# Set $end to the end of list but keep $start at the lower index.
$end = @dict.end;
# Loop until we end up on the upper index of range.
while $start < $end {
# Divide the list into 2 parts. Adds 1 because we have to find
# the upper index in this part. `div' performs Interger
# division, output is floor'ed.
my Int $mid = (($start + $end) div 2) + 1;
# Check if $mid word is lt (less than) $str. If true then
# discard the bottom end of the list, if not then discard the
# top end.
if $str lt @dict[$mid].substr(0, $str.chars).lc {
$end = $mid - 1;
} else {
$start = $mid;
}
}
# Found the upper index.
$upper = $end;
with @dict[$lower..$upper] -> @list {
# Maybe the word doesn't exist in the list, in that case there
# will be a single element in @list. We return an empty list
# unless that single element starts with $str.
if @list.elems == 1 {
return () unless @list[0].starts-with($str);
}
return @list;
}
}
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